Calculate the theoretical amount of the extracted acid using the value of Kd obt

Question

Calculate the theoretical amount of the extracted acid using the value of Kd obtained in the first part, and see how it compares with the experimental extraction. Please show me the steps. This is (B) from Part 2 as you can see. (If you have any idea, can you tell me what "the efficiency of the one-step with the two-step extraction" means here? Meaning which extraction results are more accurate?)

Given: 49 mL of 0.01998 M benzoic acid solution (couldn't get exact 50 mL), 5.0 mL of methylene chloride and "another" 4.9 mL of methylene chloride (couldn't get exact 5 mL), 0.0201 M NaOH solution (titration) used: 31.6 mL

Part 1:
the amount of acid neutralized (unextracted) = 0.0613 g
the Kd for the extraction of benzoic acid with methylene chloride = 4.860

What is the volume of aqueous layer used for titration? Isn't that 31.6 mL? "0.0201 M NaOH solution (titration) used: 31.6 mL"

Explanation / Answer

Kd = [A] [B]/[AB]

First thing You can easily calculate Kd and left over solution by given concentrations of solutions and titration value.

Second thig is, you exactly right, they asked you to find efficiency between two methods of extraction.Obviously second method will be more efficient than first.

Yes its equals to volume of NaOH by acid and both will be equivalent.

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