An object attached to a spring is displaced by 4cm and released to set it into o
ID: 582267 • Letter: A
Question
An object attached to a spring is displaced by 4cm and released to set it into oscillation with a period of time T. Later, the same object on the same spring is displaced by 8cm and set into oscillation again. What is the period of the second oscillation?
A. T
B. T/2
C. 2T
D. 4T
The speed of sound in steel is 5000 m/s. What is the wavelength of a sound wave of frequency 660 Hz in steel?
A. 7.58 m
B. 2.41 m
C. 0.829 m
D. 1.21 m
E. 1.132 m
The equation for a certain oscillator is x(t)=(2.5m)sin(4t). The amplitude and the period of oscillation are, respectively,
A. 2.5 m and 0.5 s
B. 2.5 m and 0.25 s
C. 5 m and 2 s
D. 0.3 m and 4 s
E. 2.5 m and 4 s
As a simple harmonic oscillator decreases in amplitude under the influence of friction,
A. Period and frequency both decrease
B. Total mechanical energy and frequency both decrease
C. Total mechanical energy decreases and period increases
D. Total mechanical energy decreases and frequency remains constant
When bombarded with visible light, the chlorophyll molecule readily absorbs light with wave length of 465 (cyan) and 665 (red). The reason for this is:
A. All other frequencies destructively interfere with each other near the molecule
B. Chlorophyll natural oscillates with a frequency that matches cyan and red light
C. Cyan and red constructively interfere with the chlorophyll molecule
D. Chlorophyll naturally resonates with green light, which is why it appears green.
Blowing across a tube open at both ends produces a musical note. If you place your finger over the open end at the bottom of the tube and blow across the top of the tube, a second note is produced. Compare the pitch and frequency of the second note to the pitch and frequency of the original note
A. The second note has a higher pitch and twice the frequency
B. The second note has a higher pitch and half the frequency
C. The second note has a lower pitch and twice the frequency
D. The second note has a lower pitch and half the frequency
Explanation / Answer
Multiple questions I am allowed to answer only 1 question at a time According to the chegg guidelines so I am answering question 2).
The speed of sound in steel is 5000 m/s. What is the wavelength of a sound wave of frequency 660 Hz in steel?
A. 7.58 m =================================answer)
B. 2.41 m
C. 0.829 m
D. 1.21 m
E. 1.132 m
Explanation : ====================================================================
we know that lambda = c/f
we need to find the value of lambda = 5000 m/s / 660 Hz = 7.575 m or 7.58 m ======answer)
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