Consider the 604 N weight held by two cables shown below. The left-hand cable ha

Question

Consider the 604 N weight held by two cables shown below. The left-hand cable had tension 550 N and makes an angle of with the wall. The right-hand cable had tension 610 N and makes an angle of 01 with the ceiling. N 01 604 N a) What is the angle which the right- hand cable makes with respect to the ceiling? Round up to four significant digits. Express unit as "degrees" Answer in units of degrees 008 (part 2 of 2) 10.0 points b) What is the angle which the left-hand cable makes with respect to the wall? Round up to four significant digits. Express unit as "degrees

Explanation / Answer

Let the Tension in the left handed cable = T1 = 550 N
Let the Tension in the Right handed cable = T2 = 610 N

Now,
T1* sin() = T2*cos(1)
550 * sin() = 610 * cos(1)
sin() = 1.11 * cos(1) ---------1

T1* cos() + T2*sin(1) = 604
550 cos() + 610 *sin(1) = 604 ------2

Solving eq 1 & 2
(1.11 * cos(1) )^2 + (1.09 - 1.11 *sin(1))^2 = 1
1.2321 * cos^2(1) + 1.09^2 + 1.2321*sin^2(1) - 2*1.09*1.11*sin(1) = 1
- 2*1.09*1.11*sin(1) = 1 - 1.2321 - 1.09^2
1 = 35.87o

= sin^-1[1.11 * cos(35.87)]
= 64.09 o

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