Given the enzyme-catalyzed reaction: E + S double head arrow ES rightarrow E + P
ID: 59068 • Letter: G
Question
Given the enzyme-catalyzed reaction: E + S double head arrow ES rightarrow E + P What is the rate of ES formation? The steady state of an enzyme-catalyzed reaction is reached when The concentration of enzyme-substrate complex equals the concentration of product The concentration of the enzyme-substrate complex is constant over time Z The rate of enzyme-substrate formation is constant Z The rate of appearance of the product over time is constant K_m can best be described as: dissociation constant, equal to K_d. substrate concentration to reach v_max. substrate concentration required to reach half of v_max.Explanation / Answer
1. k-1([Et] - [ES])[S]
Where Et = Total enzyme concentration, [ES] = concentration of enzyme-substrate complex and [S] = concentration of substarte.
2. the concentration of the enzyme-substrate complex is constant over time.
The steady-state of an enzyme catalyzed reaction is reached when, the concentration of the enzyme-substrate complex is constant over time.
3. substrate concentration required to reach half of Vmax
Km (michaelis menten constant) is the substrate concentration required to reach half of Vmax (half of maximum velocity)
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