E) there is no change. 17) According to the collision theory in gaseous molecule

Question

E) there is no change. 17) According to the collision theory in gaseous molecules, collision frequency i is because A) high, high, each collision results in a reaction B) low, high, molecules are moving so fast that each reaction causes man C) low, low, molecules are so far apart D) high, relatively low, only a fraction of the collisions lead to a reaction E) low, low, molecules must collide before they can react 18) For the reaction 2HgCl2+ C2042- -products, data are: [HgCI2] 0.0836 0.0836 0.0418 M [C2042-1 0.202 0.404 0.404 M Init. rate 0.26 1.04 0.53 M/hr The rate law is Rate = [HigCbp [C2042-y·Thus: A)x=1,y=2 B)x=1,y=1 c) x = 2, y = 1 D) x = 0,y=2 19) What is the rate law for the following reaction and its mechanism? 203 -302 03-02+Oo (S) O+03-202 (F) (overall reaction) A) Rate = k[O3]/(02] B) Rate = k[03P C) Rate k[O3] D) Rate = k[O3 RI02] E) Rate= k[03][02]

Explanation / Answer

Q18

In order to calculate the rate law expression for a A+B reaction, we need to apply Initial Rates Method.

Note that the generic formula goes as follows:

r = k [A]^a [B]^b

Note that if we got at least 3 sets of point, in which we have A and B constant, then we could use:

r1 / r2 = (k1 [A]1^a [B]1^b) / (k2 [A]2^a [B]2^b)

If we assume K1 and K2 are constant, then K1= K2 cancel each other

r1 / r2 = ([A]1^a [B]1^b) / ( [A]2^a [B]2^b)

Then, order according to [A] and [B]

r1 / r2 = ([A]1/[A2])^a * ([B]1/[B]2)^b

If we get two points in which A1 = A2, then we could get B, and vise versa for A...

From the data shown in YOUR table

point 1 and 2,

[C2O4-2] changes

(0.26/1.04) = (0.202/0.404)^a

a = ln((0.26/1.04) )/ln( (0.202/0.404) = 2

2nd order with respect to C2O4-2

then, choose points 2 and 3

(1.04/0.53) = 0.0836/0.0418)^b

b = ln((1.04/0.53) )/ln((0.0836/0.0418))

b = 1

then, 1st order with respec tto HgCl2

then x = 1, y = 2

choose A

Q19

choose slow mechanism since it is the one determining reaction

there is only 1 reactant

so

Rate = k*[O3]

only

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.