Calculate the molality (m) of diethyl ether in a solution preparedby combining 3

Question

Calculate the molality (m) of diethyl ether in a solution preparedby combining 3.31 L of the solute diethyl ether with 5320 mL of thesolvent (CH3)2CO.


Molar Mass (g/mol) (C2H5)2O 74.12 (CH3)2CO 58.05 Density ( kg/m3 ) (C2H5)2O 713.8 (CH3)2CO 789.9 Name/Formula diethyl ether (C2H5)2O acetone (CH3)2CO Calculate the molality (m) of diethyl ether in a solution preparedby combining 3.31 L of the solute diethyl ether with 5320 mL of thesolvent (CH3)2CO.


Molar Mass (g/mol) (C2H5)2O 74.12 (CH3)2CO 58.05 Density ( kg/m3 ) (C2H5)2O 713.8 (CH3)2CO 789.9 Name/Formula diethyl ether (C2H5)2O acetone (CH3)2CO

Explanation / Answer

The amount of the diethyl ether present in thesolution = Volume * density of the ether                                                                     = 3310mL* 0.7134g/mL [ conversion of the given densityin to g/cm3]                                                                     = 2361g Similarly the mass ofsolvent                         = 5320 mL*0.789g/mL                                                                     = 4197g Therefore number of moles of diethyl ether present inthe solution = 2361g/74.12g/mol                                                                                                   = 31.85 moles Therefore molality of the solution   = numberof moles of solute / mass of the solvent (in kg)                                                     = 31.85 mole / 4.197kg                                                     = 7.58 m

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