8.5g of NaNO3 is added to a calorimeter with 100mL of water toform a 1.0M soluti

Question

8.5g of NaNO3 is added to a calorimeter with 100mL of water toform a 1.0M solution. The temperature lowers from 23C to 18C. Theheat capacity of the calorimeter is 10J/C. Calculate the change inenthalpy. Also if I were to find the Entropy, I would divideH by T ? For Gibb's Free-energy, I would use G =H - TS ? ----------------------------------------------------------- My attempt: q = -108.5g(4.184J/gC)(-5C) + (10J/C)(-5C) = 2.2 KJ H = 2.2/.1mol = 22 KJ For S I got 73.8 J/K For G = 11 Thanks 8.5g of NaNO3 is added to a calorimeter with 100mL of water toform a 1.0M solution. The temperature lowers from 23C to 18C. Theheat capacity of the calorimeter is 10J/C. Calculate the change inenthalpy. Also if I were to find the Entropy, I would divideH by T ? For Gibb's Free-energy, I would use G =H - TS ? ----------------------------------------------------------- My attempt: q = -108.5g(4.184J/gC)(-5C) + (10J/C)(-5C) = 2.2 KJ H = 2.2/.1mol = 22 KJ For S I got 73.8 J/K For G = 11 Thanks

Explanation / Answer

make sure all your values share equivalent units

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