Considering reaction: 3H2(g) + N2(g) -->2NH3(g) and using data table Hf S Gf H2(

Question

Considering reaction: 3H2(g) + N2(g) -->2NH3(g)    and using data table Hf S Gf H2(g) 0 kJ/mol 130.6 J/mol 0 kJ/mol N2(g) 0 kJ/mol 191.5 J/mol 0 kJ/mol NH3(g) -45.9 kJ/mol 193 J/mol -16 kJ/mol Calculate S, H, G, Gf with thegiven data table above. Thank u lifesaver!! (please show steps if possible so that Imay understand how to complete this problem) thank u! (there is a second part to this question) Considering reaction: 3H2(g) + N2(g) -->2NH3(g)    and using data table Hf S Gf H2(g) 0 kJ/mol 130.6 J/mol 0 kJ/mol N2(g) 0 kJ/mol 191.5 J/mol 0 kJ/mol NH3(g) -45.9 kJ/mol 193 J/mol -16 kJ/mol Calculate S, H, G, Gf with thegiven data table above. Thank u lifesaver!! (please show steps if possible so that Imay understand how to complete this problem) thank u! (there is a second part to this question) Hf S Gf H2(g) 0 kJ/mol 130.6 J/mol 0 kJ/mol N2(g) 0 kJ/mol 191.5 J/mol 0 kJ/mol NH3(g) -45.9 kJ/mol 193 J/mol -16 kJ/mol

Explanation / Answer

      We Know that :         The given Reactionis :         3H2(g) + N2(g) -->2NH3(g)       S reaction  = S products - Sreactants                             = 2 x 193 J / K  - [ 3 x 130.6 + 191.5 ] J / K                             = -197.3 J / K        Hreaction   = H products - H reactants                              = 2 x -45.9 KJ - [ 0 + 0 ]                                  = -91.8 KJ         G0    = G0 products - G0 reactants                               = 2 ( -16 ) KJ - [ 0 + 0 ]                                                                = -32 KJ           G reaction = H reaction - T Sreaction                                 = - 91.8 x 103 J - 298 K x-197.3 J / K                                 = - 33.004 KJ

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