4. 2/2 points 3/3 submissions Notes Question: VSOrgChem5 11.kas.11. Question par

Question

4.2/2 points3/3 submissionsNotesQuestion: VSOrgChem5 11.kas.11. Question part Points 1 2 3 0.66 0.66 0.68 Total 2/2 (a) Choose the most stable alkene.
1-pentene, 3-methyl-1-butene, trans-2-pentene 1 3-methyl-1-butene 4.2/2 points3/3 submissionsNotesQuestion: VSOrgChem5 11.kas.11. 4.2/2 points3/3 submissionsNotesQuestion: VSOrgChem5 11.kas.11. Question part Points 1 2 3 0.66 0.66 0.68 Total 2/2 (a) Choose the most stable alkene.
1-pentene, 3-methyl-1-butene, trans-2-pentene 1 3-methyl-1-butene Question part Points 1 2 3 0.66 0.66 0.68 Total 2/2 (a) Choose the most stable alkene.
1-pentene, 3-methyl-1-butene, trans-2-pentene 1 3-methyl-1-butene Question part Points 1 2 3 0.66 0.66 0.68 Total 2/2 Question part Points 1 2 3 0.66 0.66 0.68 Total 2/2 Question part Points Question part Points 1 2 3 0.66 0.66 0.68 Total 2/2 Total 2/2 (a) Choose the most stable alkene.
1-pentene, 3-methyl-1-butene, trans-2-pentene 1 3-methyl-1-butene 1 3-methyl-1-butene 1 3-methyl-1-butene 1 1 2 3 0.66 0.66 0.68

Explanation / Answer

oh, i have to clarify the first answer. a) 3-(bromomethyl)-pentane. In other words, on the third carbon,there is going to be a methyl group substituent. This methyl groupwill have a bromine attached. So on the third carbon there will beCH2Br sticking out. b)1-bromo-3-methylcyclobutane. The methyl and bromine are onopposite sides of the square. c)1-bromo-2,2-dimethylcyclohexane

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