Calculate the pressure exerted by a column of mercury 70.0 cm high.The density o

Question

Calculate the pressure exerted by a column of mercury 70.0 cm high.The density of mercury is 13.5951 g/cm^3. PV=nRT. R = 0.08206L*atm/mol*K. 1 atm = 101,325 Pa = 760 Torr. g=9.8 m/s^2. 1 kgm/s^2 = 1 N. 1 N/m^2 = 1 Pa. P=hdg. Express the pressure in pascals.
The answer should be 9.33*10^4 Pa. --- I did 70^3 to get cm^3 as the unit and then tried to multipleby the density of mercury and g...but then I realized that theunits didn't cancel out. I got stuck from that point, because Ican't figure out how to cancel out units in order to get onlypascals. Any help would be appreciated! 1 kgm/s^2 = 1 N. 1 N/m^2 = 1 Pa. P=hdg. Express the pressure in pascals.
The answer should be 9.33*10^4 Pa. --- I did 70^3 to get cm^3 as the unit and then tried to multipleby the density of mercury and g...but then I realized that theunits didn't cancel out. I got stuck from that point, because Ican't figure out how to cancel out units in order to get onlypascals. Any help would be appreciated! Express the pressure in pascals.
The answer should be 9.33*10^4 Pa. --- I did 70^3 to get cm^3 as the unit and then tried to multipleby the density of mercury and g...but then I realized that theunits didn't cancel out. I got stuck from that point, because Ican't figure out how to cancel out units in order to get onlypascals. Any help would be appreciated!

Explanation / Answer

Well, i have done it by simple relations. i dont know if that willhelp you, but anyway there it goes: if 76 cm of mercury exerts a pression of excatly 1 atm; then 70 cmwill exert 0,92105263 atm. we know that 1 atm is 101325 Pa, so 0.92105263 there will exert93325.65773 Pa, or 9.332565773*10^4 Pa. thats the solution you needed. I hope to have helped

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