Calculate: 1) the percent carbon in capsaicin C18H27NO3. 2) the percent oxygen i

Question

Calculate: 1) the percent carbon in capsaicin C18H27NO3. 2) the percent oxygen in estradiol C18H24O2 3) the percent Pt in PtCl2(NH3)2 4) the percent hydrogen in ammonium sulfate
I do not know how to do this. Can anyone help? 1) the percent carbon in capsaicin C18H27NO3. 2) the percent oxygen in estradiol C18H24O2 3) the percent Pt in PtCl2(NH3)2 4) the percent hydrogen in ammonium sulfate
I do not know how to do this. Can anyone help? 2) the percent oxygen in estradiol C18H24O2 3) the percent Pt in PtCl2(NH3)2 4) the percent hydrogen in ammonium sulfate
I do not know how to do this. Can anyone help? I do not know how to do this. Can anyone help?

Explanation / Answer

1) the percent carbon in capsaicin C18H27NO3.
Molar mass of C18H27NO3 is = 18 * 12 + 27 * 1 + 14 + 3 * 16= 305g 305 g of C18H27NO3 contains 18 * 12 g of C So % mass of C = ( mass of C / mass of C18H27NO3 ) * 100                          = ( 216 / 305 ) * 100                          = 70.8 % 2) the percent oxygen in estradiol C18H24O2 Molar mass of C18H24O2 is = 18 * 12 + 24 * 1 + 2 * 16 =272 g 272 g of C18H24O2 contains 2*16 g of O % O = ( mass of O / mass of C18H24O2 ) * 100         = ( 32 / 272 ) *100         = 11.76 % 3) the percent Pt in PtCl2(NH3)2 Molar mass of PtCl2(NH3)2 is = 195 + 2 * 35.5 + 2 ( 14 + 3* 1) = 300 g % Pt = ( mass of Pt / mass of PtCl2(NH3)2 0 * 100          = ( 195 / 300) * 100          = 65 % 4) the percent hydrogen in ammonium sulfate, (NH4)2SO4 Molar mass of (NH4)2SO4 is = 2 ( 14 + 4 * 1 ) + 32 + 4 * 16 =132 g % H =( mass of H / Mass of (NH4)2SO4 ) * 100        = ( 8*1   / 132) * 100        = 6.06 %

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