How many kg/h of 90wt% propylene glycol and 1wt% propylene glycol must be combin
ID: 702375 • Letter: H
Question
How many kg/h of 90wt% propylene glycol and 1wt% propylene glycol must be combined to produce 1000L/h of 1M propylene glycol solution? Given: MW of propylene glycol = 76 g/mol. a. Write out the system of linear equations that describes the problem. b. Represent the system of linear equations from 2(a) in matrix form. Write down the commands that need to be entered in MATLAB’s Command Window to generate the coefficient matrix (A) and the constant vector (b) for the system of equations in Problem 2. c. Specify the command that uses MATLAB’s built-in linear equation solver to solve the system of equations in Problem 2 and stores the results in a column vector x. d. After solving the system of equations in MATLAB, be sure to also write out explicitly the values of flowrate obtained (kg/h) for the 90 wt% & the 1 wt% propylene glycol streams.
Explanation / Answer
Total volume to mixed per hour = 1000 L
Per hour, Let x kg of 90% glycol mixed with y kg of 1% glycol to get 1 M glycol
1 Mole glycol = 76 gm
=> in 1000 L, Total glycol = 76*1000=76000 g = 76 kg
=>x*.9+y*.01=76
Density of water = 1 kg/litre
=>x*(1-.9)+y*(1-.01)=1000
=>.1*x+.99*y=1000
=>.1*x+.99*(76-.9*x)/.01=1000
=>x=73,3 kg/hr
=>y=(1000-.1*73.3)/.99=1002.69 kg/hr
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