How many grams of ice at -16.1 ?C can be completely converted to liquid at 15.0

Question

How many grams of ice at -16.1 ?C can be completely converted to liquid at 15.0 ?C if the available heat for this process is 5.97×103 kJ ?For ice, use a specific heat of 2.01 J/(g??C) and ?Hfus=6.01kJ/mol. Express your answer to three significant figures and include the appropriate units.

Part A How many grams of ice at -16.1 C can be completely converted to liquid at 15.0 °C if the available heat for this process is 5.97x103 kJ?For ice, use a specific heat 2.01 J/(g. and AH 6.01kJ /mol fus Express your answer to three significant figures and include the appropriate units. 1390 Submit Hints My Answers Give Up Review Part incorrect; One attempt remaining; Try Again

Explanation / Answer

Let the mass of water be p g

The changes involved are

H2O (s) -------> H2O(s) --------> H2O(l) -----------> H2O(l)

at -16.1C q1 at 0 C q2 at 0 C q3 at 15C

It involves three processes and three heats q1 +q2 +q3

The total heat used is given to be =5.97x103 J

Let us calculate the three heats required.

i) q1 = mass x specific heat of ice x temp. difference

= p g x 2.01 J/g x 16.1

= 32.361 p J

ii) q2 = mass x delta H(per mole)/ molar mass

= p g x 6.01 x 1000J / 18

= 333.89 p J

iii) q3 = mass x specific heat of water x difference in temperature

= p g x 4.18J/g x 15

= 62.7 pJ

The sum of the three =32.361 p +333.89 p + 62.7 p J

= 428.951 p J

This is given equal to 5.97 x103 J

Equating and solving for p , mass of water = 224.73 g

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