How many grams of ice at -17 degrees C must be added to 741 grams of water that

Question

How many grams of ice at -17 degrees C must be added to 741 grams of water that is initially at a temperature of 70 degrees C to produce water at a final temperature of 12 degrees C? Assume that no heat is lost to the surroundings and that the container has negligible mass. The specific heat of liquid water is 4190 J/kg C and of ice is 2000 J/kg C. For water the normal melting point is 0 Degrees C and the heat fusion is 334x10^3 J/kg. The normal boiling point is 100 degrees C and the heat vaporization is 2.256x10^6 J/kg.

Explanation / Answer

0.741*(70-12)*4190=(334000+2000*17+4190*12)*x x is mass of ice in kg x=0.4305kg =430.5gms

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