What is the osmotic pressure, in atm, of a 0.0020M sucrose solution at 20.0°C? E

Question

What is the osmotic pressure, in atm, of a 0.0020M sucrose solution at 20.0°C?

Ethylene glycol (EG), CH2(OH)CH2(OH), is a common automobile antifreeze. Calculate the freezing point of a solution containing 651 g of EG in 2505 g of water.

The molar mass of EG is 62.01 g/mol. Kf = 1.86 °C/m and Kb = 0.52 °C for water. A mysterious white powder could be powdered sugar (C12H22O11), cocaine (C17H21NO4), codeine (C18H21NO3), norfenefrine (C8H11NO2), or fructose (C6H12O6). When 80 mg of the powder is dissolved in 1.50 mL of ethanol (d = 0.789 g/cm3, normal freezing point –114.6 °C, Kf = 1.99 °C/m), the freezing point is lowered to –115.5 °C.What is the identity of the white powder? (a) powdered sugar, (b)cocaine, (c) codeine, (d) norfenefrine, (e) fructose.

Explanation / Answer

Sol 1 . As osmotic pressure = P = c × R × T

where C = concentration of solution , R = gas constant , T = Temperature

Now , C = 0.0020 M , R = 0.0821 L atm / K mol ,

T = 20.0°C = 293 K

So , P = 0.0020 × 0.0821 × 293 = 0.0481 atm   .

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