Calculate the standard cell potential for each of the following cells then write

Question

Calculate the standard cell potential for each of the following cells then write the overall reaction. (These rxns are given in reduction order for each half-cell.)
a. Au1+/Au//Cr3+/Cr c. Pd2+/Pd//PbSO4//Pb, SO42-
b. O2/OH1-//Cl2/Cl1- d. Ni2+/Ni//Ag1+/Ag

Explanation / Answer

Some shortforms to help you: 1) LEO goes GER (Losing Electrons Oxidation, Gaining Electrons Reduction) 2) OARC (Oxidation = anode, reduction = cathode) Step 1: Write the full equations The two half cells you have given are: 1) Ni/Ni2+ so: Ni --> Ni2+ + 2electrons (e-) 2) Cu/Cu2+ so: Cu --> Cu2+ + 2e- Step 2: Find the Eo values in a table (standard REDUCTION potentials Ni2+ + 2e- --> Ni Eo = -0.257V Cu2+ + 2e- --> Cu Eo = 0.340V Step 3: Calculate the standard cell potential I am assuming here that the teachers wants you to calculate the SPONTANEOUS cell potential (i.e. a positive value) The formula for calculating this is: E cell = E cathode - E anode Using the shortforms I mentioned earlier: Cathode= reduction Anode = oxidation So we have: Anode: Ni --> Ni2+ + 2e- Eo = -0.257V Cathode: Cu2+ + 2e- --> Cu Eo= 0.340V Ecell = Ecath - Eanode = 0.340V - (-0.257V) = 0.597V

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