Consider the reaction of chlorine with water vapor, H2O(g) to form hydrogen chlo

Question

Consider the reaction of chlorine with water vapor, H2O(g) to form hydrogen chloride and oxygen:

1/2 Cl2(g) + H2O(g) <=> HCl(g) + 1/4 O2(g) Delta H = 28.6 kJ

(a) What is the enthalpy change for the reverse reaction?

Delta H reverse = __ kJ/mol.

(b) Balance the forward reaction with whole-number coefficients. What is H for the reaction represented by this equation?

Delta H = __ kJ/mol.

Explanation / Answer

Glucose is C6H12O6 A: C6H12O6 + O2 --> xCO2 + y H2O Have 6 carbon atoms, so get 6 CO2 molecules C6H12O6 + O2 --> 6CO2 + y H2O Have 12 hydrogen atoms, so get 6 H2O molecules C6H12O6 + O2 --> 6 CO2 + 6 H2O Now count the oxygen atoms on the product side: 12 from CO2 and 6 from H2O for 18 total Have 6 oxygen atoms in glucose, Need 12 more oxygen atoms, so need 6 oxygen molecules Final equation: C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O B: Fe2S3 + x HCl --> y FeCl3 + z H2S 2 iron atoms in Fe2S3 will yield 2 FeCl3 Fe2S3 + xHCL--> 2FeCl3 + z H2S 3 sulfur atoms in Fe2S3 will yield 3 H2S Fe2S3 + x HCl --> 2 FeCl3 + 3 H2S Count the hydrogen atoms on the product side- 3H2S means 6 hydrogen atoms. Count the chlorine atoms on the product side- 2 FeCl3 means 6 chlorine atoms Means that 6 HCl molecules are needed on the reaction side. Final equation: 1 Fe2S3 + 6 HCl --> 2 FeCl3 + 3 H2S C: CS2 + NH3 --> NH4SCN + H2S 1 carbon on the reactant side and 1 on the product side 2 sulfur on the reactant side and 2 on the product side 2 nitrogen on the product side, need 2 on the reactant side 2 NH3 will give 6 hydrogen atoms on the reactant side, have 6 hydrogen atoms on the product side Final equation: CS2 + 2 NH3 --> NH4SCN + H2S

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