Calculate the mass defect and nuclear binding energy per nucleon of the each of

Question

Calculate the mass defect and nuclear binding energy per nucleon of the each of the nuclides indicated below. Part A. O-16 (atomic mass = 15.994915 amu) Express your answer using five decimal places. Mass defect =____amu Part B. Express your answer using four significant figures. Binding energy per nucleon = ______MeV/nucleon Part C. Mo-92 (atomic mass = 91.90681 amu) Express your answer using five decimal places. Mass defect = _____ amu Part D. Express your answer using four significant figures. Binding energy per nucleon = _____ MeV/nucleon Part E. S-32 (atomic mass = 31.97207 amu) Express your answer using five decimal places. Mass defect = ________amu Part F. Express your answer using four significant figures. Binding energy per nucleon = ______MeV/nucleon

Explanation / Answer

Mass defect = m x c2

where c = speed of light

m = Neme + Nnmn + Npmp - M

M= atomic mass, Ne = no. of electrons in one atom, Np = no. of protons, Nn = no. of nuetrons and Me, Mp, Mn their respective masses.

electron mass = 0.000548579867 atomic mass units

proton mass = 1.00727638 atomic mass units

neutron mass = 1.0086654 amu

find in amu m = 8 x  0.000548579867 + 8 x 1.00727638 + 8 x1.0086654 - 15.994915 = 0.13700 amu

Mass defect = m = 0.13700 amu

Binding energy = m x c2 = m (in amu) x 931.6 MeV =127.6359 MeV

Binding energy per nucleon = (Binding energy) /(Np + Nn) = 127.6359/16 =7.97724 MeV/nucleon

Similar calculations for Sulphur with Ne = Np = Nn = 16

m = 0.291774 amu

BE = 271.8171

BE/nucleon = BE/32 = 8.49428 Mev/nucleon

Hope it helps :)

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