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Calculate the mass defect and nuclear binding energy per nucleon of the each of

ID: 996058 • Letter: C

Question

Calculate the mass defect and nuclear binding energy per nucleon of the each of the nuclides indicated below.

Part A O-16 (atomic mass = 15.994915 amu) Express your answer using five decimal places. Mass defect = amu S

Part B Express your answer using four significant figures. Binding energy per nucleon = MeV/nucleon

Part C Ni-58 (atomic mass = 57.935346 amu) Express your answer using five decimal places. Mass defect = amu

Part D Express your answer using four significant figures. Binding energy per nucleon = MeV/nucleon

Part E S-32 (atomic mass = 31.97207 amu) Express your answer using five decimal places. Mass defect = amu Part F

Express your answer using four significant figures. Binding energy per nucleon = MeV/nucleon

Explanation / Answer

Part A O-16 (atomic mass = 15.994915 amu) Express your answer using five decimal places. Mass defect = amu S

Mass defect = m x c2

where c = speed of light

m = Neme + Nnmn + Npmp - M

M= atomic mass, Ne = no. of electrons in one atom, Np = no. of protons, Nn = no. of nuetrons and Me, Mp, Mn their respective masses.

electron mass = 0.000548579867 atomic mass units

proton mass = 1.00727638 atomic mass units

neutron mass = 1.0086654 amu

find in amu m = 8 x  0.000548579867 + 8 x 1.00727638 + 8 x1.0086654 - 15.994915 = 0.13700 amu

Mass defect = m = 0.13700 amu

Part B Express your answer using four significant figures. Binding energy per nucleon = MeV/nucleon

Binding energy = m x c2 = m (in amu) x 931.6 MeV =127.6359 MeV

Binding energy per nucleon = (Binding energy) /(Np + Nn) = 127.6359/16 =7.97724 MeV/nucleon

Part C Ni-58 (atomic mass = 57.935346 amu) Express your answer using five decimal places. Mass defect = amu

mass of Ni-58 = 57.935346 amu
number of protons = 28
mass of protons in Ni = 28 * 1.00728 = 28.20384
mass of neutrons = (58 - 28) * 1.00866 = 30.2598
total mass of nucleons = 28.20384 + 30.2598 = 58.46364
mass defect (dm)= 58.46364 - 57.935346 = 0.528294

Part D Express your answer using four significant figures. Binding energy per nucleon = MeV/nucleon

binding energy = dm * 931.5 MeV
               = 0.528294 * 931.5
               = 492.106 MeV
Binding energy per nucleon = 492.106/58 = 8.4846 MeV

Part E S-32 (atomic mass = 31.97207 amu) Express your answer using five decimal places. Mass defect = amu

Similar calculations for Sulphur with Ne = Np = Nn = 16

m = 0.291774 amu

Part F

Express your answer using four significant figures. Binding energy per nucleon = MeV/nucleon

BE = 271.8171

BE/nucleon = BE/32 = 8.49428 Mev/nucleon

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