Calculate the lattice energy of AgCl using the following data: Ag(s) => Ag(g) ?H

Question

1. Calculate the lattice energy of AgCl using the following data:
   Ag(s) => Ag(g) ?H = +284 kJ/mol
   Ag(g) => Ag+(g) + e- ?H = +731 kJ/mol
   Cl2(g) => 2Cl(g) ?H = +244 kJ/mol
   Cl(g) + e- => Cl-(g) ?H = -349 kJ/mol
   Ag(s) + 1/2 Cl2(g) => AgCl(s) ?H = -127 kJ/mol
   a. -1359 kJ/mol b. -1613 kJ/mol c. -93 kJ/mol d. -661 kJ/mol e. -915 kJ/mol

Calculate the lattice energy of AgCl using the following data:
Ag(s) => Ag(g) ?H = +284 kJ/mol
Ag(g) => Ag+(g) + e- ?H = +731 kJ/mol
Cl2(g) => 2Cl(g) ?H = +244 kJ/mol
Cl(g) + e- => Cl-(g) ?H = -349 kJ/mol
Ag(s) + 1/2 Cl2(g) => AgCl(s) ?H = -127 kJ/mol
a. -1359 kJ/mol b. -1613 kJ/mol c. -93 kJ/mol d. -661 kJ/mol e. -915 kJ/mol Calculate the lattice energy of AgCl using the following data:
Ag(s) => Ag(g) ?H = +284 kJ/mol
Ag(g) => Ag+(g) + e- ?H = +731 kJ/mol
Cl2(g) => 2Cl(g) ?H = +244 kJ/mol
Cl(g) + e- => Cl-(g) ?H = -349 kJ/mol
Ag(s) + 1/2 Cl2(g) => AgCl(s) ?H = -127 kJ/mol
-1359 kJ/mol -1613 kJ/mol -93 kJ/mol -661 kJ/mol -915 kJ/mol a. -1359 kJ/mol b. -1613 kJ/mol c. -93 kJ/mol d. -661 kJ/mol e. -915 kJ/mol

Explanation / Answer

- 127 = 284 + (1/2)(244) + 731 - 349 + lattice energy of AgCl

Lattice Energy of AgCl = - 915 kJ/mol.

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