NADH Passes it\'s electrons on to oxygen through a long chain of electron carrie

Question

NADH Passes it's electrons on to oxygen through a long chain of electron carriers. How much free energy (in kj/mol) can in principle be obtained form this process under standard conditions (pH7) for each mole of oxygen that is reduced to water? The overall reaction can be summarized as follows:

2 NADH + 2 H+ + O2 ---> 2 NAD+ + 2 H2O

Explanation / Answer

2 NADH + 2 H+ + O2 ---> 2 NAD+ + 2 H2O The reaction involves the following half-reactions: ?NAD+ + 2H+ + 2 e- ® NADH + H+ ----(1) ½O2 + 2H+ + 2 e- ® H2O ---- (2) The Go of first reaction is -60.5kJ/mol Go for second reaction is -156 kJ/mol So, the overall standard free energy of the reaction is -219 kJ/mol

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