A 15-g sample of lithium is reacted with 15 g of fluorine to form lithium fluori

Question

A 15-g sample of lithium is reacted with 15 g of fluorine to form lithium fluoride:
2Li + F2 --> 2LiF. After the reaction is complete, what will be present?
0.789 moles lithium fluoride and 1.37 moles lithium none of these 0.789 moles lithium fluoride only 2.16 moles lithium fluoride only 2.16 moles lithium fluoride and 0.395 moles fluorine A 15-g sample of lithium is reacted with 15 g of fluorine to form lithium fluoride:
2Li + F2 --> 2LiF. After the reaction is complete, what will be present?
0.789 moles lithium fluoride and 1.37 moles lithium none of these 0.789 moles lithium fluoride only 2.16 moles lithium fluoride only 2.16 moles lithium fluoride and 0.395 moles fluorine 0.789 moles lithium fluoride and 1.37 moles lithium none of these 0.789 moles lithium fluoride only 2.16 moles lithium fluoride only 2.16 moles lithium fluoride and 0.395 moles fluorine 0.789 moles lithium fluoride and 1.37 moles lithium

Explanation / Answer

moles of lithium=15/7

=2.143

moles of fluorine=15/38

=0.3947

so moles of LiF formed=0.3947*2

=0.789 moles

moles of Li left=2.143-0.789

=1.37 moles

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