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Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the e

ID: 790833 • Letter: C

Question

Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?
Consider the reaction Mn7+(aq) + 2Cu+(aq) -> Mn5+(aq) + 2Cu2+(aq). What is the equivalent mass of Mn in this reaction?



Explanation / Answer

equivalent mass = molecular mass / no. of electrons lost or gained by 1 molecule or n-factor


since here no. of electrons gained by Mn is 2 as one molecule of Mn+7 is changing into 1 molecule of Mn+5

so n-factor is 2 and atomic mass of Mn is 55 g/mole


so equivalent mass = 55/2 = 27.5

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