Calculate the volume of oxygen The physical fitness of athletes is measured by V

Question

Calculate the volume of oxygen

The physical fitness of athletes is measured by Vo2 max, which is the maximum volume of oxygen consumed by an individual during incremental exercise (for example, on a treadmill). An average male has a VO2max of 45 mL 02/kg body mass/min, but a world-class male athlete can have a VO2max reading of 88.0 mL 02 /kg body mass/min. Part A Calculate the volume of oxygen, in mL, consumed in 1 hr by an average man who weighs 1801bs and has a VO2max reading of 48.0mL 02/kg body mass/min. Part B If this man lost 161bs, exercised, and increased his Vo2max to 65.4mL 02/kg body mass/min, how many mL of oxygen would he consume in 1 hr?

Explanation / Answer

1 lbs is equal to 0.45359237 kilogram

so, 189 lbs= 189*0.45359237== 85.7289579 kg

189-16 = 173 lbs= 173*0.45359237== 78.47148 kg

so a. volume o2 consumed= 85.7289579*48*60== 246899.399 ml

b.

volume o2 consumed= 78.47148 *65.4*60=307922.088 ml

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