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CH 09 HW Plus or minus Dalton\'s Law of Partial Pressure Resources Plus or minus

ID: 859528 • Letter: C

Question

CH 09 HW Plus or minus Dalton's Law of Partial Pressure Resources Plus or minus Dalton's Law of Partial Pressure A 1.00 L flask is filled with 1.05g of argon at 25 Degree C. A sample of ethane vapor is added to the same flask until the total pressure is 1.050atm . Part A What is the partial pressure of argon, PAr , in the flask? Express your answer to three significant figures and include the appropriate units. PAr=0.613 atm Part B What is the partial pressure of ethane, P ethane, in the flask? Express your answer to three significant figures and include the appropriate units. P ethane=0.377 atm

Explanation / Answer

we know

PV = nRT

n = moles of gases

T = 298 K; V = 1litre ; R = 0.0821

moles of argon (n) = 1.05 / 39.94 = 0.0262 moles

initial pressure when argon only present in flask ;

P = nRT/V = 0.64

after adding ethane vapour;

we know Pt =1.05 atm

V = 1 litre ; n is changed due to addition of ethane

finding n;

n = PtV/RT = 0.0429 moles

total moles = 0.0429

0.0429 = moles of Ar + moles of ethane

moles of ethane = 0.0167

Par = Pt * mole fraction of Ar = 0.641 atm

Pethane = Pt*mole fraction of ethane = 0.408 atm

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