CH 09 HW Plus or minus Dalton\'s Law of Partial Pressure Resources Plus or minus
ID: 859528 • Letter: C
Question
CH 09 HW Plus or minus Dalton's Law of Partial Pressure Resources Plus or minus Dalton's Law of Partial Pressure A 1.00 L flask is filled with 1.05g of argon at 25 Degree C. A sample of ethane vapor is added to the same flask until the total pressure is 1.050atm . Part A What is the partial pressure of argon, PAr , in the flask? Express your answer to three significant figures and include the appropriate units. PAr=0.613 atm Part B What is the partial pressure of ethane, P ethane, in the flask? Express your answer to three significant figures and include the appropriate units. P ethane=0.377 atmExplanation / Answer
we know
PV = nRT
n = moles of gases
T = 298 K; V = 1litre ; R = 0.0821
moles of argon (n) = 1.05 / 39.94 = 0.0262 moles
initial pressure when argon only present in flask ;
P = nRT/V = 0.64
after adding ethane vapour;
we know Pt =1.05 atm
V = 1 litre ; n is changed due to addition of ethane
finding n;
n = PtV/RT = 0.0429 moles
total moles = 0.0429
0.0429 = moles of Ar + moles of ethane
moles of ethane = 0.0167
Par = Pt * mole fraction of Ar = 0.641 atm
Pethane = Pt*mole fraction of ethane = 0.408 atm
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