Consider the following reaction: The rate law for this reaction is: Rate = k [HB

Question

Consider the following reaction:

The rate law for this reaction is:

Rate = k [HBr(g)] [O2(g)]

At a certain temperature when [HBr(g)] = 0.00375 M and [O2(g)] = 0.00315 M, the rate of this reaction is 9.04e-02 M s-1. What is the reaction rate when the concentration of HBr(g) is doubled, to 0.0075 M, while the concentration of O2(g) is 0.00315 M?

a) The reaction rate is 1.81e-01 M s-1.
b) The reaction rate is 4.52e-02 M s-1.
c) The reaction rate is 7.65e+03 M s-1.
d) The reaction rate is 3.62e-01 M s-1.
e) The reaction rate is 9.05e-02 M s-1.

Explanation / Answer

e) The reaction rate is 9.05e-02 M s-1.

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