Calculating the reduced mass of (need to use isotopic masses) 1. a diatomic fluo

Question

Calculating the reduced mass of (need to use isotopic masses)

1. a diatomic fluorine molecule, 19F-19F.

2. a hydrogen atom, taking the proton and the electron to be the two “ends” of the oscillator.

3. a He+ ion, taking the 4He nucleus and the electron to be the two “ends” of the oscillator.

4. with the three calculations above, as the difference in the masses of the oscilator's ends increases. What value does the reduced mass approximate? in terms of the dynamics of the vibrations, why does this make physical sense?

Thanks,

Explanation / Answer

1) reduced mass = 1/m1 + 1/m2

Reduced mass = 1/19 + 1/19 = 19+19 / 19 X 19 = 0.105

2) Hydrogen atom

Mass of electron = 9.1 × 10-31 Kg

mass of proton = 1.67 × 10-27 Kg

reduced mass = 1/me + 1/mp

reduced mass = 1/ 9.1 × 10-31   + 1/ 1.67 × 10-27 = 1.098 X 10^30 + 0.598 X 10^27 = 10^27 ( 1098 + 0.598 ) = 1098.598 X 10^27

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