Consider the reaction CaSO4( s )Ca2+( a q )+SO24( a q ) At 25 C the equilibrium

ID: 895665 • Letter: C

Question

Consider the reaction
CaSO4(s)Ca2+(aq)+SO24(aq)
At 25 C the equilibrium constant is Kc=2.4×105 for this reaction.

Part A

If excess CaSO4(s) is mixed with water at 25 C to produce a saturated solution of CaSO4, what is the equilibrium concentration of Ca2+?

Express your answer to two significant figures and include the appropriate units.

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Part B

If excess CaSO4(s) is mixed with water at 25 C to produce a saturated solution of CaSO4, what is the equilibrium concentration of SO24?

Express your answer to two significant figures and include the appropriate units.

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Part C

If the resulting solution has a volume of 1.9 L , what is the minimum mass of CaSO4(s) needed to achieve equilibrium?

Consider the reaction
CaSO4(s)Ca2+(aq)+SO24(aq)
At 25 C the equilibrium constant is Kc=2.4×105 for this reaction.

Part A

If excess CaSO4(s) is mixed with water at 25 C to produce a saturated solution of CaSO4, what is the equilibrium concentration of Ca2+?

Express your answer to two significant figures and include the appropriate units.

SubmitMy AnswersGive Up

Part B

If excess CaSO4(s) is mixed with water at 25 C to produce a saturated solution of CaSO4, what is the equilibrium concentration of SO24?

Express your answer to two significant figures and include the appropriate units.

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Part C

If the resulting solution has a volume of 1.9 L , what is the minimum mass of CaSO4(s) needed to achieve equilibrium?

CaSO4(s)<---> Ca2+(aq)+SO2-4(aq)
X X

Concentration of both Ca2+ and SO42- will be same at equilibirum

Kc = [Ca2+] [SO42-]
2.4*10^-5 = X*X
X=0.0049 M

a)
Answer: 0.0049 M

b)
0.0049 M

c)
Concentration of CaSO4 should be atleast 0.0049 M
Volume = 1.9 L
So,
number of moles of CaSO4 = M * V = 0.0049*1.9 = 0.00931 mol

Molar mass of CaSO4 = 136 g/mol

Mass of CaSO4 required= number of moles * volume =0.00931*136 = 1.27 g
Answer: 1.27 g

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