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Please note, I just need help with the final question. This is long, because I w

ID: 895838 • Letter: P

Question

Please note, I just need help with the final question. This is long, because I wanted to include all of the information that I have. There's 3 questions involved in this problem; I have the answers to the first 2, but I only need help with question 3.

This is from a lab, so I'll try to provide the most information that I can.

Since the standard is known to contain 0.50 % wt asorbic acid, multiply the mass weighed on the balance, and recorded by 0.0050. Don't forget to convert to mg. This will be the mass of the unknown acid. (The value should be in the range of 1-2mg)

The mass weighed on the balance was - 00.300 g

To solve this, the 00.300 g needs to be converted to mg, and then it needs to be multiplied by 0.005. I just don't know how to do that.

mass asorbic acid in standard = ? mg - The answer to this is 1.5 mg

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Question 2 -

Using the number of drops of DCP for the standard (which was 17), the number of drops of DCP for the drink sample (which was 11), and the known mass of asorbic acid calculated in question 1 above,   what is the mass of asorbic acid in the drink sample?

This calculation requires this equation - (mass vitaminC) unknown = (mass vitaminC) known X drops DCP unknown over (like a fraction)drops DCP known

mass asorbic acid in drink = ? mg - The answer to this is 0.975

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Question 3 -

Compute the mass of asorbic acid in juice sample using the mass of asorbic acid in the known, and the number of drops of DCP used for the known and for the Juice sample.

Mass asorbic acid in Juice = ? mg    mass ascorbic acid in juice= 0.5*x/17 ( where x is th number of drops of DCP in unknown)     This is the one I need help with.

Thanks so much for any help in advance!

Explanation / Answer

Solution :-

Q3)

Mass of ascorbic acid in the known saple which used 17 drop of the DCP is 1.5 mg

Therefore for the unknown it used 11 drops of DCP

Therefore the mass of the ascorbic acid in the unknown = 1.5 mg * 11 drop / 17 drop

                                                                                                       = 0.9706 mg

Ao the mass of the ascorbic acid in the unknown sample of juice is 0.9706 mg

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