Given that the molar mass of H3PO4 is 97.994 grams, determine the # of grams of

Question

Given that the molar mass of H3PO4 is 97.994 grams, determine the # of grams of H3PO4 needed to prepare 0.35 L of a 1.25 M H3PO4 solution, now what volume, in liters, of a 1.25 M H3PO4 solution can be prepared by diluting 50 mL of a 4.5 M H3PO4 solution? Given that the molar mass of H3PO4 is 97.994 grams, determine the # of grams of H3PO4 needed to prepare 0.35 L of a 1.25 M H3PO4 solution, now what volume, in liters, of a 1.25 M H3PO4 solution can be prepared by diluting 50 mL of a 4.5 M H3PO4 solution?

Explanation / Answer

(a) Number of Moles of H3PO4 = 350/1000*1.25 = 0.4375 moles

Number of grams of H3PO4 = 0.4375*97.994 = 42.8723 gms

(b) let the volume in liters be x

then x * 1.25 = 50/1000*4.5

x = 0.18 liters = 180 ml

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.