Calculate the number of moles of CO 2 evolved in each beaker. The molecular weig

Question

Calculate the number of moles of CO2 evolved in each beaker. The molecular weight of CO2 is 44.01 g/mole CO2.

Calculate the number of moles of NaHCO3 that reacted in each beaker. (The molar ratio between evolved CO2 and the bicarbonate, HCO3-, is 1:1).

Calculate the mass of NaHCO3 that was used up in the reaction for each beaker. The molecular weight of NaHCO3 is 84.007 g/mole.

Lab notes

beaker weight- 85 grams

Before AS

b1: 115.000g

b2: 115.005g

b3: 115.011g

b4: 115.016g

b5: 115.021g

b6: 115.027g

+ alka Seltzer

b1: 117.318g

b2: 117.241g

b3: 117.164g

b4: 117.133g

b5: 117.138g

b6: 117.143g

Explanation / Answer

Beaker 1 :-

Mass of CO2 evolved = 0.682

moles of CO2 evolved = mass/molar mass = 0.682/44.01 = 0.0155

moles of NaHCO3 consumed = moles of CO2 evolved = 0.0155

Thus, mass of NaHCO3 consumed = moles*molar mass = 0.0155*84.007 = 1.302 g

Beaker 2 :-

Mass of CO2 evolved = 0.764

moles of CO2 evolved = mass/molar mass = 0.764/44.01 = 0.0174

moles of NaHCO3 consumed = moles of CO2 evolved = 0.0174

Thus, mass of NaHCO3 consumed = moles*molar mass = 0.0174*84.007 = 1.458 g

Beaker 3 :-

Mass of CO2 evolved = 0.847

moles of CO2 evolved = mass/molar mass = 0.847/44.01 = 0.0192

moles of NaHCO3 consumed = moles of CO2 evolved = 0.0192

Thus, mass of NaHCO3 consumed = moles*molar mass = 0.0192*84.007 = 1.617 g

Beaker 4 :-

Mass of CO2 evolved = 0.883

moles of CO2 evolved = mass/molar mass = 0.883/44.01 = 0.0201

moles of NaHCO3 consumed = moles of CO2 evolved = 0.0201

Thus, mass of NaHCO3 consumed = moles*molar mass = 0.0201*84.007 = 1.685 g

Beaker 5 :-

Mass of CO2 evolved = 0.883

moles of CO2 evolved = mass/molar mass = 0.883/44.01 = 0.0201

moles of NaHCO3 consumed = moles of CO2 evolved = 0.0201

Thus, mass of NaHCO3 consumed = moles*molar mass = 0.0201*84.007 = 1.685 g

Beaker 6 :-

Mass of CO2 evolved = 0.884

moles of CO2 evolved = mass/molar mass = 0.883/44.01 = 0.0201

moles of NaHCO3 consumed = moles of CO2 evolved = 0.0201

Thus, mass of NaHCO3 consumed = moles*molar mass = 0.0201*84.007 = 1.685 g

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