When excess solid YZ is put in water and allowed to dissolve the following equil

Question

When excess solid YZ is put in water and allowed to dissolve the following equilibrium reaction occurs and the equilibrium table shown can be set up.

[initial]   excess 0 0

[change] x +x +x

[equilibrium] excessx excess+x excess+x

The amount of solid that dissolves is called the molar solubility, denoted here by x. Since the concentration of the solid is constant and is not included in the Ksp expression, the equilibrium expression for the reaction is Ksp=[Y][Z], or, in terms of molar solubility, Ksp=x2.

Ksp expression for C2D3 in terms of the molar solubility x.

108x5

C2D3 has a solubility product constant of 9.14×109. What is the molar solubility of C2D3?

Ksp expression for C2D3 in terms of the molar solubility x.

108x5

Explanation / Answer

First express the Ksp expression for C2D3 in terms of molar solubility X.

C2D3 = (2x )2( 3x) 3 = 108 x 5

9.14 x 10-9 = 108 x 5

X= 9.67 x 10-3

So molar solubility = 9.67 x 10-3

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