What is the value of sE ( internal energy) in kJ for the reaction? (10pts) (VCal
ID: 931419 • Letter: W
Question
Explanation / Answer
(V)
We know that
Delta H for the reaction = [sum of heat of formation for products] - [sum of heat of formation for reactants]
Delta H of reaction = [12 X Delta H of formation of CO2 + Delta H formatio of 6H2O] - [2x Delta H formation of C6H6]
(-6534) = [(12)(-393.5) + (6)(-285.8)] - (2 X delta H of formation of benzene)
(-6534) = -6436.8 - (2 X delta H of formation of benzene)
(2 X delta H of formation of benzene) = 97.2
delta H of formation of benzene) = +48.6 kJ,
(VI ) table not given
(VII) if temperature and moles are constant then
P1V1 = P2V2
P1 = 150 atm
V1 = 49 L
P2 = 1.02 atm
V2 = ?
V2 = 49 X 150 / 1.02 = 7205.88 L
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