How much dry solute would you take to prepare each of the following solutions fr

Question

How much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?

Part A

125 mL of 0.105 M NaNO3

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Part B

123 g of 0.220 m NaNO3

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Part C

123 g of 2.0 % NaNO3 solution by mass

Express your answer using two significant figures.

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Part D

How much solvent would you take to prepare the solution in part B?

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Part E

How much solvent would you take to prepare the solution in part C?

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How much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?

Part A

125 mL of 0.105 M NaNO3

msolute =   gNaNO3  

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Part B

123 g of 0.220 m NaNO3

msolute =   gNaNO3  

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Part C

123 g of 2.0 % NaNO3 solution by mass

Express your answer using two significant figures.

msolute =   gNaNO3  

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Part D

How much solvent would you take to prepare the solution in part B?

msolvent =   gH2O  

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Part E

How much solvent would you take to prepare the solution in part C?

msolvent =   gH2O  

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Explanation / Answer

1) 0.105M means 0.105 moles in 1L solution

therefore in 125 mL moles = 0.105/1000 * 125 = 0.013 moles = 0.013 * 85 (Molecular weight of NaNO3) = 1.11g

2) ).22m means 0.22 moles of NaNO3 in 1 Kg of solvent, therefore moles = 0.222 * 0.123 = 0.027 moles = 2.32 g

3) 2% of NaNO3 by mass means in 100 g of solution there are2 g of NaNO3

therefore in 123g = 2/100 * 123 = 2.46g

4) 123 g of solvent

5) 123 - 2.46 = 120.54 g

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