Consider the following reaction: S2O82-(aq) + 3 I-(aq) 2 SO42-(aq) + I3-(aq) (a)

Question

Consider the following reaction: S2O82-(aq) + 3 I-(aq) 2 SO42-(aq) + I3-(aq) (a) The rate law for this reaction is first order in S2O82-(aq) and first order in I-(aq). What is the rate law for this reaction?

D)Rate = k [S2O82-(aq)] [I-(aq)]

A)Rate = k [S2O82-(aq)]2 [I-(aq)]

B)Rate = k [S2O82-(aq)] [I-(aq)]2

C)Rate = k [S2O82-(aq)]2 [I-(aq)]2

D)Rate = k [S2O82-(aq)] [I-(aq)]3

E)Rate = k [S2O82-(aq)]4 [I-(aq)]

(b) If the rate constant for this reaction at a certain temperature is 0.00421, what is the reaction rate when [S2O82-(aq)] = 0.0529 M and [I-(aq)] = 0.0645 M? Rate = M/s. (c) What is the reaction rate when the concentration of S2O82-(aq) is doubled, to 0.106 M while the concentration of I-(aq) is 0.0645 M? Rate = M/s

Explanation / Answer

a ) Rate = k [S2O82-(aq)] [I-(aq)]

reason : first order with respect to each species . and total order = 1 + 1 = 2

b)

rate = 0.00421 x 0.0529 x 0.0645

rate = 1.436 x 10^-5 M/s

c)

rate = 0.00421 x 0.106 x 0.0645

rate = 2.88 x 10^-5 M/s

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