The ?G°of the reaction is -4.470 kJ ·mol–1. Calculate the equilibrium constant f

Question

The ?G°of the reaction is -4.470 kJ ·mol–1. Calculate the equilibrium constant for the reaction. (Assume a temperature of 25° C.)

Consider a general reaction Mapd Mapddt enzyme The G. of the reaction is-4.470 kJ·mol-1. Calculate the equilibrium constant for the reaction. (Assume a temperature of 25° C.) 4470 kJ mof! Calculate the equlbrium constant for the Number What is G at body temperature (37.0° C) if the concentration of A is 1.7 M and the concentration of B is 0.80 M? body temperature (37.0 Number kJ mol

Explanation / Answer

a)

dG° = -4.47 kJ.

T = 25 °C = 298 K

then; apply ratio:

dG° = -RT*lnK

-4470 = -8.314*298*lnK

K =exp( 4470 /(8.314*298)) = 6.07502

K = 6.07502

b)

T = 37°C = 37+273 = 310 K

R = 8.314

M = 1.7 M of A and M = 0.8 B

Q = [B]/[A]

Q = 0.8/1.7 = 0.470588

Then

dG = dG° - Rt*lnQ

then

dG = -4470 - 8.314*310*ln(0.470588) = -2527.27 J

dG = -2.527 kJ

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