A student measures the potential of a cell made up with 1 M CuSO_4 in one soluti

Question

A student measures the potential of a cell made up with 1 M CuSO_4 in one solution reservoir and 1 M ZnSO_4 in the other. There is a metallic copper (Cu^degree) electrode in the CuSO_4 and a metallic zinc (Zn^0) electrode in the ZnS)_4. and the cell is set up as shown in Figure 32.1. She finds that the potential, or voltage. of the cell. E^0_cell. is 1.076V. and that the Zn electrode is negative. At which electrode is oxidation occurring Write the equation for the oxidation half-reaction in this cell. Write the equation for the reduction half-reaction in this cell. d. Write the net ionic equation for the spontaneous oxidation-reduction reaction that occurs in this cell.

Explanation / Answer

we know that

in voltaic cel

anode is the negative electrode

given

Zn electrode is negative

so

Zn is anode

also

we know that

oxidation takes place at anode

So

oxidation takes place at Zn electrode

b)

the oxidation half reaction takes place at anode

Zn (s) ---> Zn+2 (aq) + 2e-

c)

the reduction half reaction takes place at cathode

Cu+2 (aq) + 2e- --> Cu (s)

d)

the overall equation is

Zn (s) + Cu+2 (aq) ---> Zn+2 (aq) + Cu (s)

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