Calculate the standard reaction enthalpy for the following two reactions using o

Question

Calculate the standard reaction enthalpy for the following two reactions using only mean bond enthalpies in Table 1.4 (slide 1.5.9) for the first reaction and the mean bond enthalpies along with the appropriate thermodynamic data from Resource Section 3 for the second reaction equation. For part b) you will use the result of part a) and also need to use the standard formation enthalpies of CCl4 (g) and CCl4 (l), as well as those for HCl (g) and HCl (aq). The formation enthalpy for CCl4 (l), as well as those for HCl (g) and HCl (aq) can be found in the Resource Section 3: Data in the Appendix of your book. The standard formation enthalpy for CCl4 (g) is equal to: - 95.7 kJ/mol a)CCl4 (g)+4H2(g)àCH4 (g)+4HCl(g) b)CCl4 (l)+4H2(g)àCH4 (g)+4HCl(aq)

Explanation / Answer

a)CCl4 (g) + 4 H2 (g) ----> CH4 (g) + 4HCl(g)
dH rxn = dH products - dH reactants
dH rxn = (-74.81+4*(-92.31))-(-135.44+4*0)
dH rxn = -308.61 kJ/mol
b)CCl4 (l) + 4 H2 (g) -----> CH4 (g) + 4HCl(aq)
dH rxn = dH products - dH reactants
dH rxn = (-74.81+4*(-167.16))-(-135.44+4*0)
dH rxn = -608.01 kJ/mol

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