Calculate with absolute error the mass, density and average density of ethanol b
ID: 1004023 • Letter: C
Question
Calculate with absolute error the mass, density and average density of ethanol based on the following laboratory measurements:
1. Mass of beaker (g), Trial 1 = 30.16 +/- .001 ; Trial 2 = 32.07 +/- .001
2. Mass of beaker + ethanol (g), Trial 1 = 34.28 +/- .001 ; Trial 2 = 36.38 +/- .001
3. Mass of ethanol (g), Trial 1 = 4.12 +/- .002 ; Trial 2 = 4.31 +/- .002
4. Volume of ethanol used (mL) = 5.0
5. Density of ethanol (g/mL), Trial 1 = .824 ; Trial 2 = .862
6. Average density of ethanol (g/mL) = .843
Explanation / Answer
ABSOLUTE ERROR = UNCERTAINTY IN THE MEASUREMENT , that is the diffrence between the true value and measured value, which is shown by +- sign , and over all is unit less.
1) mass of beaker (g) , trail 1=30.16 + 0.001 = 30.161 ,
=30.16- 0.001= 30.159,
= 30.16 +/- 0.001= absolute error =0.001,
for trail 2 = absolute error =0..001,
2) trail 1= mass of beaker + etahnol= 34.28 +/- 0.001= 0.001 absolute error,
trail 2= 36.38 +/- 0.001= 0.001 absolute error,
3) mass of ethanol (g) , trail= 4.12 +/- 0.001 = 0.001 (absolute error),
trail 2= 4.31 +/- 0.001= 0.001(absolute error),
4) volume of ethanol = 5.0 ml , 5 ml*.0843= 4.215 gms
5) density = 0.824 +/- 0.019 and 0.862 +/-0.019 ,( absolute error = 0.019 )
6) average density = 0.843
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