Concerning the electron configuration of fluorine, 1 s^2s^2P^5 which of the foll

Question

Concerning the electron configuration of fluorine, 1 s^2s^2P^5 which of the following represents the core electrons only? A) 1s^2 B) 1s^22s^2 C) 1s^22s^22p^5 D) 2s^22p^5 E) 2p^5 Which ion is isoelectronic with Ar? A) Fe^2+ B) F^- C) Br^- D) Ga^3+ E) Ca^2+ The electron configuration of a copper(I) ion is A) [Ar]4s^23d^8 B) [Ar]4s^13d^9 C) [Ar]3d^10 D) [Ar]4s^23d^64p^2 E) [Kr] Which of the elements listed below has the greatest atomic radius? A) B B)AI C) S D) P E) Si Arrange the following ions in order of decreasing ionic radius: AI^3+, Mg^2+, Na^+, O^2, decreasing radius rightarrow A) AI^3+ > Mg^2+ > O^2- > Na^+ B) AI^3+>Mg^2+>Na^+>O^2- C) Na^+>Mg^2+>AI^3+>O^2- D) O^2->AI^3+>Mg^2+>Na^+ E) O^2->Na^+>Mg^2+>AI^3+ For which of the following reactions is the enthalpy change equal to the second ionization energy of nitrogen? A) N^2+(g) rightarrow N^3+(g)+e^- B) N^2+(g) + e^- rightarrow N^+(g) C) N(g) rightarrow N^2+(g)+2e^- D) N^-(g)+e^- rightarrow N^2(g) E) N^+(g) rightarrow N^2+(g)+e^- Which of the following atoms has the greatest electron affinity (largest positive value)? A) S B) P C) Ga D) Li E) Br The electron affinity of fluorine is essentially equal to A) the negative of the ionization energy F. B) the ionization energy F^-. C) the negative of the ionization energy F^-. D) the ionization energy Ne. E) the negative of the ionization energy Ne. Which one of the following is most likely to be an ionic compound? A) CaCI_2 B) CO_2 C) CS_2 D) SO_2 E) OF_2 Which one of the following is most likely to be a covalent compound? A) Rb_2O B) BaO C) SrO D) SeO_2 E) MnO_2 The Lewis dot symbol for the chloride ion is A) CI B) CI C):CI^- D) CI^- E) CI^-

Explanation / Answer

15 => A) 1s2 => Core electrons: Core electrons are the electrons in an atom that are not valence electrons and therefore do not participate in bonding.

16. E) Ca2+ => Isoelectronic: Which species has same number of electrons Ar (18 electrons), Ca2+ (18 electrons), Electronic configuration=> [Ar] (or) 1s2 2s2 2p6 3s2 3p6

17 => C) [Ar] 3d10 => Cu1+ ion => One electron removed from 4s shell.

18 => B) Al => Al is a third element of third period, it preceeded over Si, P, S => by moving across left to right in a period the atomic radius gradually decreases.

19 => E) O2- > Na+ > Mg2+ > Al3+ => With increasing charge of the ion the ionic radii decreases.

25 => B)

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