a patient is suspected of having a low stomach acid a condition known as hypochl

Question

a patient is suspected of having a low stomach acid a condition known as hypochloridia, to determine takes 17 ml of her gastric juices and titrates .000279 M KOH gastric juice sample required 4.03

Sapling Learning A patient is suspected of having low s whether the sample with 0.000279 M KOH. The gastric juice sample required 4.03 mL of the KÖH titrant to neutralize it. tomach acid, a loridia. To determine her gastric juices and titrate the Calculate the pH of the gastric juice sample. Assume the sample contained no ingested food or drink might otherwise intertere with the titration. uice sample Assume the sample contained no ingested food or drink which Number For the patient to be suffering from hypochloridia, the pH of the gastric juices from the stomach must be greater than pH 4. Does the patient have hypochloridia? O Yes No O Unable to determine

Explanation / Answer

we know that

moles = molarity x volume (ml) / 1000

so

moles of KOH added = 0.000279 x 4.03 / 1000

moles of KOH added = 1.12437 x 10-6

now

KOH ---> K+ + OH-

we can see that

moles of OH- added = moles of KOH added = 1.12437 x 10-6

now

H+ + OH- --> H20

so

in a acid base titration

moles of OH- added = moles of H+ present

so

moles of H+ present in the sample = 1.12437 x 10-6

now

volume of the sample = 17 ml

we know that

concentration = moles x 1000 / volume (ml)

so

[H+] = 1.12437 x 10-6 x 1000 / 17

[H+] = 6.61394 x 10-5

now

pH = -log [H+]

pH = -log 6.61394 x 10-5

pH = 4.18

so

pH of the gastric juice sample is 4.18

2) we got pH = 4.18

so

in this case

pH = 4.18 > 4

so

Yes , the patient have hypochloridia

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