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To standardize your NaOH, you titrate 20.0 ml of 0.0769 M HCl solution, measurin

ID: 1037556 • Letter: T

Question

To standardize your NaOH, you titrate 20.0 ml of 0.0769 M HCl solution, measuring the pH after each small addition of NaOH.

Show all work for full credit. Copy you lab report. r answers to problems I through 3 into your lab notebook for use when writing your rdize your NaOH solution, you titrate 20.0 ml of 00769 M HCI solution, measuring the pH after each small addition of NaOH. Below is the graph you obtain experimentally. The equivalence point occurs where there is a steep rise in pl What molar quantity of HCl is being 1 titrated? Titration of lin with NadiH 12 10 What molar quantity of NaOH has been added at the equivalence point? e Low What volume of NaOH solution has been added at the equivalence point? 2 245 10 12 14 16 18 20 22 24 26 28 3 Volume of Base Expanded view of the equivalence point 10 What is the concentration of the NaOH solution? 22 2324 25 2627 Volume of Base 255

Explanation / Answer

[HCl] = 0.0769 M

Volume of HCl = 20 mL = 0.02 L

a)

Molar quantity of HCl = [HCl] * Volume of HCl

= 0.0769 M * 0.02 L

= 0.00154 mol

b)

Molar quantity of NaOH at equivalence point

= Molar quantity of HCl

= 0.00154 mol

c)

Volume of NaOH added at equivalence point

= Volume at which there sharp increase in pH in the graph

= 24 mL = 0.024 mL

d)

[NaOH] = Molar quantity of NaOH at equivalence point / Volume of NaOH added at equivalence point

= 0.00154 mol / 0.024 mL

= 0.064 M

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