Yellow: y = 0.0063x + 0.0068 R² = 0.99739 Blue: y = 0.0029x - 0.0012 R² = 0.9979

Question

Yellow:

y = 0.0063x + 0.0068

R² = 0.99739

Blue:

y = 0.0029x - 0.0012
R² = 0.99797

Part IV: Determine the concentration of Unknown 2 (green dye: FD & C Yellow 5 + FD & C Blue 1) Yellow Absorbance of Unknown 2:. 2at mx-325.nm Blue Absorbance of Unknown 2: Base 26 at d on your calibration plot, show your work below and determine the concentration of FD & C Yellow 5 dye in Unknown 2, include units Concentration of FD & C Yellow 5: Based on your calibration plot, show your work below and determine the concentration of blue dye in Unknown 2, include units: Concentration of FD & C Blue 1:

Explanation / Answer

From the R2 values of both the calibration curves we can say that calibration curves are straight (almost!).
The calibration curve is Absorbance vs Concentration in mole/dm3
From the straight line graph we can calculate unknown concentration using line equation:
For FD&C yellow equation is:
y = 0.0063 x + 0.0068
Thus, put value , y = 0.52 as an absorbance of FD&C yellow 5 in yellow absorbance in given equation for Yellow: y = 0.0063x + 0.0068
R² = 0.99739:
so,
x = (0.52 - 0.0068) / 0.0063 = 81.46 mole/dm3= Concentration of FD&C yellow 5

Now, put y = 0.36 as an absorbance of FD&C blue 1 in blue absorbance in given equation for Blue: y = 0.0029x - 0.0012,
x = (0.36+0.0012) / 0.0029 = 124.55 mole/dm3= concentration of FD&C blue 1

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