In treating spinal injuries, it is often necessary to provide some tension along

Question

In treating spinal injuries, it is often necessary to provide some tension along the spinal column to stretch the backbone. One device for doing this is the Stryker frame, illustrated in part (a) of the figure. A weight W is attached to the patient (sometimes around a neck collar as shown in part (b) of the figure), and friction between the person's body and the bed prevents sliding! If the coefficient of static friction between a 98.5kg patient's body and the bed is 0.785, what is the maximum traction force along the spinal column that W can provide without causing the patient to slide? Under the conditions of maximum traction, what is the tension in each cable attached to the neck collar?

Explanation / Answer

1

Maximum T when W is just balanced by maximum friction force i.e =coefficient of friction*m*g = 0.785*98.5*9.8 = 757.76 N

2

If tension in one wire is T then its component along main wire is Tcos35

So 2Tcos25 = 757.76N = 418.04 N

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