In treating spinal injuries, it is often necessary to provide some tension along

Question

In treating spinal injuries, it is often necessary to provide some tension along the spinal column to stretch the backbone. One device for doing this is the Stryker frame, illustrated in part (a) of the figure. A weight W is attached to the patient (sometimes around a neck collar, as shown in part (b) of the figure), and friction between the person's body and the bed prevents sliding.(Figure 1)

Part A

If the coefficient of static friction between a 88.5 kg patient's body and the bed is 0.90, what is the maximum traction force along the spinal column that W can provide without causing the patient to slide?

Express your answer in newtons to three significant figures.

Part B ) Under the conditions of maximum traction, what is the tension in each cable attached to the neck collar?

Explanation / Answer

A)
Normal force on the body, N = m*g

= 88.5*9.8

= 867.3 N

maximum traction, W = N*mue_s

= 867.3*0.9

= 780.57 N <<<<<<------Answer

B) Let T is the tension in the strings.

From figure, 2*T*sin(65) = w

==> T = w/(2*sin(65)

= 780.57/(2*sin(65))

= 430.63 N <<<<<------Answer

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