A 2.10 kg steel ball strikes a massive wall at 12.8 m/s at an angle of alpha = 5

Question

A 2.10 kg steel ball strikes a massive wall at 12.8 m/s at an angle of  alpha = 53.0? with the plane of the wall. It bounces off with the same speed and angle (as seen in the figure below).

If the ball is in contact with the wall for 0.186 s, what is the magnitude of the average force exerted on the ball by the wall?

A 2.10 kg steel ball strikes a massive wall at 12.8 m/s at an angle of alpha = 53.0½ with the plane of the wall. It bounces off with the same speed and angle (as seen in the figure below). If the ball is in contact with the wall for 0.186 s, what is the magnitude of the average force exerted on the ball by the wall?

Explanation / Answer

here there is no change in momentum in y -diretion.

Apply, impulse = chnage in momentum

F*dt = -m*v2**sin(alfa) - m*v*sin(alfa)

here, |v1| = |v2|, so

F*dt = -2*m*v*sin(alfa)

|F| = 2*m*v*sin(alfa)/dt

= 2*2.1*12.8*sin(53)/0.186

= 230.83 N

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