A cylinder with a piston contains 0.200 mol of nitrogen at 1.70×10 5 Pa and 320
ID: 1326745 • Letter: A
Question
A cylinder with a piston contains 0.200 mol of nitrogen at 1.70×105 Pa and 320 K . The nitrogen may be treated as an ideal gas. The gas is first compressed isobarically to half its original volume. It then expands adiabatically back to its original volume, and finally it is heated isochorically to its original pressure.
Need part H and I. it is not 50.5 J
Part A
Find the work done by the gas during the initial compression.
-266
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Part B
Find the heat added to the gas during the initial compression.
-930
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Correct
Part C
Find internal-energy change of the gas during the initial compression.
-664
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Correct
Part D
Find the work done by the gas during the adiabatic expansion.
Enter your answers numerically separated by commas.
161
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Correct
Part E
Find the heat added to the gas during the adiabatic expansion.
0
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Part F
Find the internal-energy change of the gas during the adiabatic expansion.
-161
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Correct
Part G
Find the work done by the gas during the final heating.
0
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Part H
Find the heat added to the gas during the final heating.
?
Incorrect; Try Again; 5 attempts remaining
Part I
Find the internal-energy change of the gas during the final heating.
?
W =-266
JExplanation / Answer
A) W1 = -266 J
B) Q1 = -930 J
C) delta_U1 = -664 J
D) W2 = +161 J
E) Q2 = 0
F) delta_U2 = -161 J
G) W3 = 0
H) let Q3 is the heat added to the system.
In the whole process there is no net change in internal energy
because Internal energy is a state function.
dU = dU1 + dU2 + dU3
0 = dU1 + dU2 + dU3
==> dU3 = -dU1 - dU2
= 664 + 161
= 825 J
so, when heat is added at constanr volume, workdone W3 = 0
so, dQ3 = dU3 + dW3
dQ3 = dU3
= 825 J <<<<-----Answer
I) dU3 = 825 J <<<<-----Answer
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