A block of mass m = 2.60 kg is pushed a distance d = 2.50 m along a frictionless

Question

A block of mass

m = 2.60 kg

is pushed a distance

d = 2.50 m

along a frictionless, horizontal table by a constant applied force of magnitude

F = 16.0 N

directed at an angle

= 26.0°

below the horizontal as shown in the figure below.

(a) Determine the work done on the block by the applied force.
J

(b) Determine the work done on the block by the normal force exerted by the table.
J

(c) Determine the work done on the block by the gravitational force.
J

(d) Determine the work done by the net force on the block.
J

Explanation / Answer

m = 2.60 kg
d = 2.50 m
F = 16.0 N
= 26.0°

(a)
Net Force in the Direction of movement, = F*cos(26)

= 16.0 * cos(26)
= 14.4 N

Work Done = Force * Distance
W = 14.4 * 2.5 J
W = 36 J
Work done on the block by the applied force = 36 J

(b)
As there is no motion in the Vertical Direction -
Work done on the block by the normal force exerted by the table = 0

(c)
As there is no motion in the Vertical Direction -
Work done on the block by the gravitational force = 0

(d)
Only work done is by the External Force applied , Therefore
Net Work done = 36 J

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