A 100? resistor, a 0.100 ? F capacitor, and a 0.300H inductor are connected in p

Question

A 100? resistor, a 0.100?F capacitor, and a 0.300H inductor are connected in parallel to a voltage source with amplitude 240V .

Part A

What is the resonance angular frequency?

Part B

What is the maximum current through the source at the resonance frequency?

Part C

Find the maximum current in the resistor at resonance.

Part D

What is the maximum current in the inductor at resonance?

Part E

What is the maximum current in the branch containing the capacitor at resonance?

Part F

Find the maximum energy stored in the inductor and in the capacitor at resonance.

Explanation / Answer

1/Z = 1/R + j(wC-1/wL)
at resonance

w = 1/root(LC) = 5773.5

A). current through inductor = 240/wL = 0.138 A
B). current through Capacitor = 240 *w*C = 0.138 A
C). Max energy stored in inductor = 0.5LI^2 = 2.85mJ
Max energy stored in capacitor = 0.5CV^2 = 2.88mJ

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