A block of mass m = 3.70 kg is pushed a distance d = 7.60 m along a frictionless

Question

A block of mass m = 3.70 kg is pushed a distance d = 7.60 m along a frictionless, horizontal table by a constant applied force of magnitude F = 16.0 N directed of an angle theta = 21.0 degree below the horizontal as shown in the figure below. Determine the work done on the block by the applied force. Determine the work done on the block by the normal force exerted by the table. Determine the work done on the block by the gravitational force. Determine the work done by the net force on the block.

Explanation / Answer

W is the product of Force and the displacement in the direction of foce. (W = F x d cos theta)

(a) cos componant of F is in the direction of displacement.

F cos theta = 14.93 N

W = F cos theta x d = 14.93 x 7.6 = 113.46 J

(b) Normal reaction is perpendicular to displacement so cos theta = cos (90) = 0

So W = 0

(c)Gravitational force is perpendicular to displacement so cos theta = cos (90) = 0

So W = 0

(d) The net force is the cos component of F so as answer (a)

W = F cos theta x d = 14.93 x 7.6 = 113.46 J

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